Aerowerx
Well-Known Member
I wasn't sure if this should go here on in the wood forum. Anyway...
Maybe I didn't have the right words, but couldn't find my answer using search.
So, my rather long winded question:
Lets say you have a 1/2 inch bolt going through three pieces of wood. There is a force on the joint so that the bolt is in double shear.
How do you determine the force on the wood? Lets say that each piece of wood is 1 inch thick. Would you use the hole diameter times the wood thickness, which would be 0.5 square inches? So the force on the wood (in psi) would be the force on the joint divided by 0.5?
Or do you use some other calculation, since the bolt is round?
Which is more critical in this case, compression or tension on the wood?
How does the force spread out to where the wood is attached?
Maybe I didn't have the right words, but couldn't find my answer using search.
So, my rather long winded question:
Lets say you have a 1/2 inch bolt going through three pieces of wood. There is a force on the joint so that the bolt is in double shear.
How do you determine the force on the wood? Lets say that each piece of wood is 1 inch thick. Would you use the hole diameter times the wood thickness, which would be 0.5 square inches? So the force on the wood (in psi) would be the force on the joint divided by 0.5?
Or do you use some other calculation, since the bolt is round?
Which is more critical in this case, compression or tension on the wood?
How does the force spread out to where the wood is attached?
