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Richard Hiscocks Book: chordwise lift distribution calculations

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Cubman

Member
Joined
Mar 31, 2013
Messages
21
Location
John Bunyan country, GB and Touraine, F
A fellow can stay silent and be thought a fool, or speak up and have it confirmed:ermm:, so here I am busy working through the calculations for determining chordwise lift load distributions. My maths is not great, but I am keen to fully understand the methods of analysis in qualitative terms and then crunch the quantitatve parts in a more monkey see monkey do manner, whilst having an understanding for the limitations of the process and the appropriateness of the application.

The equation Cmc/4 = -0.10 x Clb (10.1) appears on page 146, and then is modified for the calculations on page 151 to Mc/4 = -C/10 x Nb (also 10.1) I have calculated my rib loads and they seem sensible.

However, although it is probably staring me in the face, I do not follow how the -0.1 term is derived for Cm in the first equation. I know the Moment used for the second equation has the actual Cm for the section used, but the x 0.1 or /10 term is still there mocking me.

Is this all to do with areas being equal to unity?

Cub
 
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