Aerowerx
Well-Known Member
I want to make sure I have the correct understanding of this.
As I understand it, if you have a wood beam, supported at both ends, and apply a downward force at the mid point, when the force reaches the modulus of rupture the beam will fail. I guess it is roughly equivalent to the Elastic Limit of a metal.
If you use Hickory, for example, it has a modulus of rupture of 20,200 psi, and is one of the strongest hardwoods. So, if you have a beam with a 1 inch by 1 inch cross section, it will support up to 20,200 pounds before failure? Seems incredible, doesn't it?
Yes, I know that is an average value (or maximum value?), but still....
Of course, it may bend a long time before it actually fails. Maybe that is the limitation instead of the Modulus of Rupture.
As I understand it, if you have a wood beam, supported at both ends, and apply a downward force at the mid point, when the force reaches the modulus of rupture the beam will fail. I guess it is roughly equivalent to the Elastic Limit of a metal.
If you use Hickory, for example, it has a modulus of rupture of 20,200 psi, and is one of the strongest hardwoods. So, if you have a beam with a 1 inch by 1 inch cross section, it will support up to 20,200 pounds before failure? Seems incredible, doesn't it?
Yes, I know that is an average value (or maximum value?), but still....
Of course, it may bend a long time before it actually fails. Maybe that is the limitation instead of the Modulus of Rupture.
